Dengan rumus ABC 2x² +5 x+2 = 0
Jawaban:
Persamaan Kuadrat
[tex]x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]
[tex]x = \frac{ - 5± \sqrt{ {5}^{2} - 4(2 \times 2) } }{2 \times 2} [/tex]
[tex]x = \frac{ - 5± \sqrt{25 - 16} }{4} [/tex]
[tex]x = \frac{ - 5± \sqrt{9} }{4} [/tex]
[tex]x = \frac{ - 5±3}{4} [/tex]
[tex]x1 = \frac{ - 5 + 3}{4} = \frac{ - 2}{4} = - \frac{1}{2} [/tex]
[tex]x2 = \frac{ - 5 - 3}{4} = \frac{ - 8}{4 } = - 2[/tex]
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